getline problem

[bhalo]

say i will input 5 sepate strings.
then the program outputs, "input string 1: input string 2:"
why 2 at the same time?

#include <iostream>   
#include <string>  
using namespace std;

int main () 
{	
	int n;
	cout << "input number of strings: ";
	cin >> n;
	string s1[100], s2;
	
	for(int i=0; i<n; i++){
		cin.clear();
		cout << "input string " << i+1 <<": ";		
		
		getline(cin,s1[i]);
		s2 += s1[i];
	}
	
	cout << "all strings: \n";
	cout << s2;	
}

[jlb]

Probably because of the dangling new line character left in the buffer by your previous extraction. Try to ignore() the character before you enter the loop.

[TarikNeaj]

Just to clarify a bit on what @jlb said. If you first use cin >> and then switch to getline(). You will have to put a cin.ignore(); after the cin >> (becuase of the reasons @jlb stated above). Like this -

int n;
	cout << "input number of strings: ";
	cin >> n;
	cin.ignore();
	string s1[100], s2;

[bhalo]

thanks, cin.ignore(); worked.

#include <iostream>   
#include <string>  
using namespace std;

int main () 
{	
	int n;
	cout << "input number of strings: ";
	cin >> n;
	cin.ignore();
	string s1[100], s2;
	
	for(int i=0; i<n; i++){
		//cin.clear();
		cout << "input string " << i+1 <<": ";		
		
		getline(cin,s1[i]);
		s2 += s1[i];
	}
	
	cout << "all strings: \n";
	cout << s2;	
	
}