Cannot convert char to double?

[JohnOPhelan]

Could anybody tell me what's wrong with this problem. I'am an absolute beginner so don't assume anything? It's saying in the compiller that it cannot convert char to double...
/* Halving 'n'*/
#include <stdio.h>
#include <math.h>
#include <stdlib.h>

int main ()
{
double n, r;
char szInput [256];
printf("Enter the value of n: ");
gets(szInput);
n = atof(szInput);
r = szInput/2.0;
printf("Half of n is %d\n", r);
return 0;
}

Much appreciated for any help on the matter!

John

[jsmith]

szInput is a character array (string).

You can't divide a string by 2.0.

[Bazzy]

r = szInput/2.0;
r is a double, szInput a C string. What you want to do is r = n/2

[firedraco]

szInput/2.0 needs to convert szInput to a double to do the division. I think you meant to divide 'n' by two, not szInput?

EDIT: zomg triple response!

[JohnOPhelan]

Lol! I had a long day to be honest, and I can't believe I didn't spot this.

Either way a big thanks for the quick replies!