I am tasked to write a program that displays the cost of a medical conference, the total number of people, and the cost per person, given the number of people. I need to be able to add more people on as I go, and I must use a sentinel. I am stuck figuring out exactly which loop to nest. I am given the cost per person for certain ranges, so for a couple people, its a certain cost, for slightly more people, its a little less and so on. I attempted using a switch, but I am realizing that probably wont work.
#include "stdafx.h" // loads precompiled header
#include <iostream> // allows input and output
usingnamespace std; //allows all names in standard directive
// Function main begins execution
int main()
{
double cost = 0;
int people = 0;
cout << "How many people are attending the conference?\n";
top:
for (int count = 0; count != -1; count = count + people)
{
cin >> people;
switch (people)
{
case 1:
case 2:
case 3:
cost = 129.50;
break;
case 4:
case 5:
case 6:
case 7:
case 8:
case 9:
case 10:
cost = 110.50;
break;
default:
cout << "Please enter a valid integer";
goto top;
break;
}
double total = count * people;
cout << "The conference will cost $" << total << " with " << count << " people at $" << cost << " per person.\n\n";
cout << "Enter the number of additional participants.\nEnter -5 to end the program.\n";
#include <iostream>
int main(void)
{
double cost, totalcost, arbitrarycost, arbitrarycost2, arbitrarycost3;
int people;
char ans;
int arbitrarynumber;
while (ans == 'y' || ans == 'Y')
{
std::cout << "How many people will be attending?: \n";
std::cin >> people;
if (people <= arbitrarynumber)
{
totalcost = (people * arbitrarycost);
}
elseif (people > arbitrarycost2 && people <= arbitrarycost3)
{
//Same thing as above, different numbers.
}
std::cout << "The total cost for " << people << " will be: " << totalcost;
std::cout << "\nWould you like to continue? (y/n)\n";
std::cin >> ans;
}
return 0;
}
Everything worked great! Thank you so much for your help! There's only one thing I can't figure out at this point: why when using fixed precision are only my answers for 1,2, or 3 attendees (count) returning an answer for "cost" in scientific notation. ie a count of 1 returns an answer for cost as 1.3e+002 rather than 129.50.
#include "stdafx.h" // loads precompiled header
#include <iostream> // allows input and output
usingnamespace std; //allows all names in standard directive
// Function main begins execution
int main()
{
double cost = 0; // total cost
double costpp = 0; // cost per person
int count = 0; // total number of attendees
int people = 0; // number of people from an individual group
char ans = 'y'; // sentinel to prompt action
cout << "Welcome to the Conference Cost Calculator!\nYou can add more attendees by choosing to continue when prompted\n";
while (ans == 'y' || ans == 'Y') // loop will continue if "Y" or "y" is entered
{
cout << "How many people will be attending? \n\n";
cin >> people; // prompts input
count = count + people; // counter to total attendees
// if statements to determine the total cost based on the count
if (count >= 11)
{
cost = (count * 84.00);
}
elseif (count >= 4 && count <= 10)
{
cost = (count * 110.50);
}
elseif (count >= 1 && count <= 3)
{
cost = (count * 129.50);
}
double costpp = cost / count; // calculates cost per person
cout.precision(2); // answers in 2 decimal places with "fixed"
cout << "\nThe conference will cost $" << cost << fixed << " with " << count << " people at $" << costpp << fixed << " per person.\n\n"; // displays answers
cout << "Would you like to continue to add more attendees? (y/n)\n\n"; // asks user for loop decision
cin >> ans; // loop decision
cout << "\n\n"; // skips a line
} // end while loop
} // end function main
