nested for loop problem

[Nut420x]

I'm working on a program that asks for a mooses speed and a distance and the output should read the remaining distance that the moose has traveled every second

example:
Please enter the speed in m/s: 8
Please enter the distance in m: 57
The moose is 57m from its destination after 0 seconds
The moose is 49m from its destination after 1 seconds
The moose is 41m from its destination after 2 seconds
The moose is 33m from its destination after 3 seconds
The moose is 25m from its destination after 4 seconds
The moose is 17m from its destination after 5 seconds
The moose is 9m from its destination after 6 seconds
The moose is 1m from its destination after 7 seconds
The Goose has landed! Moo!


My program kind of works but has a slight glitch and doesn't quite put out the right output. Any help would be greatly appreciated. This is what my code looks like


int main()
{
int speed, distance;
do
{
cout << "Please enter the speed in M/S" << endl;
cin >> speed;
} while (speed <= 0);

do
{
cout << "Please enter the distance in M" << endl;
cin >> distance;
} while (distance <= 0);

for (int i = distance; i >= 1; i = i - speed)
{

for (int j = 0; j <= speed; j = j + 1)

{
cout << "The moose is" << i << "from its destination after" << j << endl;
}
}
cout << "The Goose Has Landed! Moo!" << endl;



system ("PAUSE");
return 0;

[kbw]

Where do you calculate remaining distance from speed?

[Nut420x]

I'm not sure exactly where to put what your saying?

[spazamatic2]

cmpt 111?

[spazamatic2]

I don't think you need a for loop. Try an if else

[Nut420x]

Yeah cmpt 111 U of S .... You?

[spazamatic2]

same

[jsmith]

You need exactly one for loop. Although there are multiple ways of writing it, I would suggest having
the loop count the number of elapsed seconds, beginning at 0. The loop's end condition is when the
moose has reached the destination.