for loop

[spazamatic2]

I need to write a program that asks for an integer and a character and prints out that many characters with only 10 per column. I can't get mine to work.
int main ()

{

int number;
int line;
char character;

cout << "please enter a positive integer" << endl;
cin >> number;
cout << "please enter a character" << endl;
cin >> character;
if (number > 0)
for ( int line=0; line< number; line++)

{ cout << character << endl;

for (int number=0; number < 9; number++)
{
cout << character;

}

[enterprize]

Firstly, your for loops' braces don't close.

Secondly, your int number=0 removes the inputted value of number.

Is the point of the program to print the character the number's times?
For example, 15 and c would yield:
cccccccccc
ccccc

If so you would need do subtract 10 from number on each loop of the outer loop.

Hope this helps.

[spazamatic2]

So I`ve fixed most of the problems I can see but now the only thing is, is that it stops at printing only 10 characters. Thank you for your help

int main ()

{

int number;
int line;
char character;

cout << "please enter a positive integer" << endl;
cin >> number;
cout << "please enter a character" << endl;
cin >> character;
if (number > 0)
for ( int line=0; line > 10; line++)

{ cout << character;
number = number - 10;
}
for (int number; number < 10; number++)
{
cout << character;
}






return 0;

}

[bluezor]

It's because
for (int number; number < 10; number++)
If you examine it, it only prints 10 times.
I suggest a for() loop -
for(int i = 0; i < number; i++)
Print character. If i is divisible by 9 without remainder (hint: modulo) because that's the 10th character, print a newline.

[spazamatic2]

I'm not sure how to do the modulo correctly. I've got it printing the right amount of characters but now it doesn't cut off at only ten per line.

int number;
int line;
char character;

cout << "please enter a positive integer" << endl;
cin >> number;
cout << "please enter a character" << endl;
cin >> character;
if (number > 0)
for ( int j=0; j > character; j++)

{ cout << character << endl;
number = number - 10;
}
for (int i; i < number; i++)
{
cout << character;
if (i%9==0);

}

[bluezor]

All you need is this loop -

if (number > 0)
{
    for (int i = 0; i < number; i++)
    {
        std::cout << character;
        if (i % 9 == 0) // if its the tenth character
            std::cout << "\n"; // newline
    }
}

Also I don't know if it's just me... but I see over 5 threads on this same topic in this forum...

[spazamatic2]

Thank you! I'm almost there I just can't get rid of the single character printing first.
It comes out:

integer = 12
character =r

r
rrrrrrrrrr
r

[firedraco]

That is because 0 mod anything is 0, try starting your loop at one and running to <= num, and change your modulus accordingly.

[spazamatic2]

Thank you so much, I've finally got it! I am VERY new to this so thank you for your patience.

[Nut420x]

I was wondering spazamatic2 how did you get your program to not print out a single character on the first line

[spazamatic2]

I had to change my int i=1 instead of 0 or else the modulo is always 0.

[Nut420x]

I did that but it still prints 1 character on the first line

this is what i got

for (int i = 1; i <= posNumber; i++)
{
std::cout << letter;
if (i % 9 == 0)
std::cout << "\n";

[spazamatic2]

just change it to i%10 instead of 9

[Nut420x]

Thanks a lot it works now!