reversing number

im writing a program to reverse number however i am having trouble with it.

ex:
input: 123
output:321


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  #include<iostream>
using namespace std;

double rev_digit(int num);


int main()
{

  int num;
  
  cout << "input number ";
  cin >> num;
  
  
  
  cout << num << endl;
  
  return 0;
}

double rev_digit(int num)
{
  
  int rev_num=0;
  while (num > 0)
  {
    rev_num= rev_num*10 + num%10;
    num = num/10;
  }
  
return rev_num;
}
closed account (2UD8vCM9)
Is there any reason you're not just computing it as a string?

Seems like you're making it unnecessarily difficult.
This algorithm will successfully reverse your entered integer.

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#include <iostream>
using namespace std;

int main(){
 int num,i=10;   
 cin>>num;   

 do{
    cout<< (num%i)/ (i/10);
    i *=10;
   }while((num*10)/i!=0);

 system("pause");
}

i need to use a function for my assignment
closed account (2UD8vCM9)
Then just put that code in a function.
Did anyone actually look at OPs code?
@axel609 your rev_digit function is correct except that the return type should be int. The problem is you do not call the function in main.
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