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Array - compare elements and extract min max values

Aybars (2)
alright, here is the problem,
i made an array of 10 people,
used for loop to input how many cookies which person ate,
then output that into a table,

on second for loop i can show who ate the most cookies.
But i cant do the same with the minimum, i can do it if there is 0 value in the array but anything more than 0 wont work.

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  #include "stdafx.h"
#include <iostream>

using namespace std;



int main()
{
	int anPersons[10];
	int nMax = 0;
	int nMin = 0;
	int nPerson;

	// Header
	cout << "element - value\n";
	// Input cookies amounts eaten!

	for (int x = 0; x <= 9; x++)
	{
		cin >> anPersons[x];
	}
	// Output table!
	cout << "**********************\n";
	for (int x = 0; x <=9; x++)
	{
		cout << "Person " << x << " ate " << anPersons[x] << " cookies.\n";
	}
	// Find cookie monster!
	for (int x = 0; x <= 9; x++)
	{
		if (anPersons[x] > nMax)
		{
			nMax = anPersons[x];
			nPerson = x;
		}
	}
	cout << "Person number " << nPerson << " ate " << nMax << " cookies.\n";
	// Find cookie hater!
	for (int x = 0; x <= 9; x++)
	{
		if (anPersons[x] <= nMin)
		{
			nMin = anPersons[x];
			nPerson = x;
		}
	}
	cout << "Person number " << nPerson << " ate: " << nMin << " cookies.\n";



cin.clear();
	cin.ignore(255, '\n');
	cin.get();
	return 0;
}
Zaita (2770)
before line 40 put:
nMin = anPersons[0];
This sets the minimum value to be initially the first person in your array. Then you can iterate over looking for someone who ate less.
Aybars (2)
wow that did it, thanks a lot
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