How to get a double value when I devide two integers????

[sha92]

Hello,
In my program I need to get a double value when I use the findValue function. But I end up getting an integer value instead. Please help!

  #include <iostream>
using namespace std;

class Rational
{
public:
	Rational(int = 0, int = 0);
	void assignnewvalues(int, int);
	void print();
	double findValue();
	

private:
	int numerator, denominator;

};

Rational::Rational(int num, int den)
{
	numerator = num;
	denominator = den;
}

void Rational::assignnewvalues(int num, int den)
{
	numerator = num;
	denominator = den;
}

void Rational::print()
{
	cout << "The rational number is: " << numerator << "/" << denominator << endl;
}

double Rational::findValue()
{
	double value= numerator / denominator;
	return value;
}

int main()
{
	Rational num1(22, 7);
	num1.print();

	cout << "The value is: " << num1.findValue() << endl;
	system("pause");
	return 0;
}

[jlb]

You will need to cast one or both of the variables to a double to force a double answer.

return static_cast<double>(numerator) / static_cast<double>(denominator);

[mutexe]

http://msdn.microsoft.com/en-us/library/c36yw7x9.aspx
doh, beaten to it.

[sha92]

That works! I never knew this. Thanks so much!