Check all values of array in one

[Nielyboyken]

Hello

I need to check if the value of array A, also exists somewhere in array B.

Pseudo code:

#include <iostream>

using namespace std;
int main() {

int a[50] = {
1,
6
};
int b[50] = {
4,
8,
1,
9
};

for (int i = 0; i < 10; i++) {
if (a[i] == b[0..5]) {
cout << a[i] << " Exists somewhere"<<endl;
}
}

}

Just Pseudo of course. :)

Possible to do this?

Thanks for reading,
Niely

[MiiNiPaa]

Is it for single value? If so, a simple linear search would suffice:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30

#include <algorithm> #include <iomanip> #include <iostream> #include <iterator> //Direct implementation bool is_in(int* begin, int* end, int value) { for( ; begin != end; ++begin) //Loop over range to search in if (value == *begin) //If we find value inside range, return true return true; return false; //If there is no such value return false } //Using standard library bool is_in_stl(int* begin, int* end, int value) { //return if value is found in range return std::find(begin, end, value) != end; } int main() { int a[] = {1, 6}; int b[] = {4, 8, 1, 9}; std::cout << std::boolalpha; //Make output pretty //Try if 1 and 6 are in b std::cout << is_in(b, b + 4, a[0]) << '\n' << //Warning, make sure that this 4 will be changed if array size changes is_in_stl(std::begin(b), std::end(b), a[1]); //Generic, STL style }

true false

http://coliru.stacked-crooked.com/a/75ed28834616079a