Need Quick Help

[rtolambiya]

hi guys could any one please solve this problem for me because it is urgent

find and display the sum of all the values,
which are ending with 2 (i.e., units place is 2). in an array of given size(two dimensional)

[beko]

Here are some hints.

You need two loops to iterate through the matrix, in the form:

for(int i=0; i < row; i++)
  for(int j=0; j < column; j++)

You can access each element via

myArray[i][j]

You can get the last digit of a number via

someInteger % 10

You can compare that number with 2 by using the == operator for instance

myNumber == anotherNumber

The result is best stored in a vector, as you may have more than one number that ends with 2:

#include <vector>
...
std::vector v;

You take the sum of all numbers by iterating through the vector and adding all values to sum

int sum = 0;
for(int i=0; i < v.size(); i++)
  ...

Edit: Even better, just leave out the vector and add the value to the sum right after you've checked that it ends with two.

[PopEye]

#include <iostream>
#include <stdlib.h>
#include <ctime>
using namespace std;

int main()
{
    const int row = 5, col = 5;
    int sum = 0;
    srand(static_cast <unsigned int> (time(0))); //seed using current time as non-negative int
    int array[row][col];

    //random data in array
    for(int i = 0; i < row; i++)
        for(int j = 0; j < col; j++)
            array[i][j] = rand() % 500 + 1; //numbers 1 - 500

    //search array
    for(int i = 0; i < row; i++)
        for(int j = 0; j < col; j++)
            if(array[i][j] % 10 == 2) //find numbers that end with 2
            {
                sum += array[i][j];
                cout << array[i][j] << endl;
            }

    cout << "-----\nSum = " << sum << endl;

    return 0;
}

[rtolambiya]

Thank you that solved my problem