Another question that confuse me - Give an advice

[PBIRBAS]

Give an advice about How many lines will be appeared in the following part of the code ?

for(i = 0; i < 5; i = i + 1)
for(j = 0; j < i; j = j + 1)
printf("%d %d\n", i, j);
I think is 5

[z05DSL3A]

for(i = 0; i < 5; i = i + 1)
for(j = 0; j < i; j = j + 1)
printf("%d %d\n", i, j);

is the same as

for(i = 0; i < 5; i = i + 1)
{
    for(j = 0; j < i; j = j + 1)
    {
        printf("%d %d\n", i, j);
    }
}

5 is wrong btw.

[PBIRBAS]

So what do you think will be the results (How many lines) ?

[mcleano]

Think about it, break it up into little steps.

i = 0 and j = 0 so j isn't less than i - therefore nothing gets prinited.

i now equals i + 1

i = 1 and j = 0 so j is now less than i - therefore i(1) is printed and j(0) is printed.

j now equals j + 1

The conidition j < i is checked and comes back false so we return to the outer loop.

The condidition i < 5 is still true so i is now equal to i(1) + 1

J is now reinitialized to 0 and the condition is checked which comes back true.

i = 2 and j = 0 so j is less than i - therefore i(2) is printed and j(0) is printed

j is incremented and and the condition is checked again which returns true as i = 2 and j = 1

i(2) and j(1) is therefore printed

and so on....

[wachtn]

Why not compile it to view the output?

[z05DSL3A]

being able to read and understand code without compiling it is an important skill to learn.