Finding mean as a double

[Khuslen]

Hi, I'm having trouble understanding how they found the mean of the integers as a double.

The question is as follows:
Given a list of N integers, find its mean (as a double), maximum value, minimum value, and range. Your program will first ask for N, the number of integers in the list, which the user will input. Then the user will input N more numbers.


The solution is this:

  #include <iostream>
using namespace std;

int main()
{
	
	int N;
	cout << "Enter N: ";
	cin >> N;
	int acc = 0;
	cout<<"Now enter each value and click 'Enter' after each one \n";
	cin >> acc;
	int minVal = acc;
	int maxVal = acc;
	
	for (int i = 1; i < N; ++i)
	{
		int a;
		cin>>a;
		
		acc+=a;
		if(a<minVal)
		{minVal=a;}
		if(a>maxVal)
		{maxVal=a;}
	}
	cout<<"Mean: "<<(double)acc/N<<"\n";
	cout<<"Max: "<<maxVal<<"\n";
	cout<<"Min: "<<minVal<<"\n";
	cout<<"Range: "<<(maxVal-minVal)<<"\n";
	return 0;
}

What I don't understand is line 27, where they found the mean by using "(double)acc/N". Isn't acc just the very first value entered and not the sum of all the integers? Any help would be appreciated.

[shadowCODE]

acc is not just the first value. Its the accumulated sum. line 21

[Khuslen]

Thank you!