multiple occurrence issue

[LATCH100]

this is part of the program. i keep getting the same index position for numbers that occur more than once. i was wondering if the answer to my problem can be found in this part?

int function2(int arr[],int SIZE, int pos)
{
 for (int a=0;a<SIZE;a++)
 {
  if(arr[a]==pos)
  {
   return a;
  }
 }
}

[LendraDwi]

There's nthing wrong here,, but what is pos ?

[LATCH100]

the values from another array. so what would i do so the second occurring number gives its actual index position instead of the first one?

[LendraDwi]

How about this, check the where it is first, then check the next one before returning it
if(arr[a+1]==pos)

[LATCH100]

that didnt work, check what first?

[LendraDwi]

Ah sorry I mean find the first ocurence of pos, then before return the index check another occurence of pos in the next position

[LATCH100]

how would i do that?

[LendraDwi]

for(int i=0;I<size-1;i++){
    if(arr[i]==pos&&arr[i+1]==pos)
    return (i+1);
}

What your program do ? I'm affrad that I. Have wrong perception

[LATCH100]

it takes the values from one array and searches for their index position in another array(linear search algorithm). i got that down except for the part i mentioned above

[LendraDwi]

Ooh I thought that you'll delete the double -.-)" or something

Sooo for ex
a[]={1,2,3,4,5,6}
Arr[]={1,2,2,3,4,5}
First step find 1 in arr, and it'll return 0
Then find 2 in array and it'll return 1 and 2 ?

[LATCH100]

^yes except it return 1 and 1 when it finds 2

[LendraDwi]

In that case don't return anything before search trough the array, just save the index in some variable

[LATCH100]

how do i do this? any thoughts?