worng output in float divid

[raminlich]

hi all

   float x,y,z;
   cin>>x>>y;
   z=x*y;
   z=z/100;

ok when i give x 5000000 ( if x is more than 4999988 out put will like this numbers 1e+06).
and y = 20 ( y must be under 100).

will give me this answer 1e+06
why? :(
i want to be normal numbers(not rounded i mean numbers do not need to be round).
thank you

[MiiNiPaa]

Because 1000000 is equal to 1e+06;

Use std::fixed to avoid scientific notation:

#include<iomanip>
//...
std::cout << std::fixed << z;