Nov 15, 2014 at 7:00am
hi, im trying to pass 3 variables from a function to main() but only the very last variable is being transferred. Can anyone give me a hint as to why?
thanks
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int main(){
double mn, avg, mx, dev;
(mn, mx, avg)=MinMaxAvg(pdata);
cout<<"\n\nFrom "<<filename<<" your data statistics are:";
cout<<"\n\n Count: "<<data.size();
cout<<"\n Minimum: "<<mn;
cout<<"\n Average: "<<avg;
cout<<"\n Maximum: "<<mx;
cout<<"\n StdDev: "<<dev;
return 0;
}
double MinMaxAvg(vector <double> *pdata){
double mnf=2.5,mxf=2.5,avgf=0;
\\stuff happens
return mnf, mxf, avgf;
}
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Last edited on Nov 15, 2014 at 7:02am
Nov 15, 2014 at 7:47am
the styte of function call is wrong(mn, mx, avg)=MinMaxAvg(pdata);
no more than one valve can be returned from function.
also the function implementation is wrong. you can only return one double value from MinMaxAvg
Nov 15, 2014 at 8:04am
thank you for the response mzzz, iv been looking this for a while but i just cant figure out where to go from here. if i do..
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void MinMaxAvg(vector <double> *pdata),double& mn, double& mx, double& avg){
double mn=2.5,mx=2.5,avg=0;
\\stuff happens
}
//then back in main()
MinMaxAvg(pdata, mn, mx, avg);
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i get a annoying error "error: expected unqualified-id defore 'double'
Thanks
Last edited on Nov 15, 2014 at 8:21am
Nov 15, 2014 at 8:36am
i got it, thanks for your help.