Program won't run "cout" after the second function

[imaghhc]

1

[MiiNiPaa]

Please use code tags when posting code. They look like <> on the right of the text box

Your code outputting fine to me:

Please enter a SINGLE Character to act as key:
e
Please enter a phrase or sentence >= 4 characters:
hello
0
I'm a function.

Notice the 0. It is here because you first replacing character with '-' and then trying to count already replaced character.

[imaghhc]

yes, but it's supposed to show the three functions after entering both the keyCharacter and str.

[MiiNiPaa]

yes, but it's supposed to show the three functions after entering both the keyCharacter and str.

int main()
{
   string keyCharacter, str;
   int count=0;
   keyCharacter = getKeyCharacter(); //First line of output and line of input
   str = getString(); //Second line of output and line of input
   str = maskLetter(str, keyCharacter); //No putput
   count = countKey(str, keyCharacter); //One number
   cout << "I'm a function. \n"; //One line
   return 0;
}

Everything you call is outputted.

[imaghhc]

1

[MiiNiPaa]

i am a ranger

it reads i, then as it is les than 4 characters it prompts to enter again, reads am, prompts again, reads a, repeat, reads ranger which finally suits conditioins.
Operator >> reads space delimited values. That means it stops readin after it encounter space. If you need whole line, use std::getline()

[imaghhc]

thank you minipaa, getline works, but "Please enter a phrase or sentence >= 4 characters: \n" is still repeating. how could i modify my loop to let in only show once whatever i enter.

[MiiNiPaa]

but "Please enter a phrase or sentence >= 4 characters: \n" is still repeating

You made a mistake somewhere. Show what you did.

[imaghhc]

i got it, ty very much.