Can someone quick tell me why this wont run?

[jrt1990]

This is driving me insane. I had it running earlier but accidentally saved over top of it so I redid it and now its not working. I cant for the life of me find out why.

Thanks, Jeremy.

  //Lab 3-1: Print out the values of square root of all 
//integers divisible by 5 between 5 and 100.

#include <iostream>
#include <math.h>
using namespace std;

void print();

int main()
{

	for (int i = 5; i <= 100; i += 5){

		print();

	}

	cin.get();
	return 0;

}

void print()
{

	cout << "The square root of " << i << " is " << sqrt(i) << "." << endl;

}

[shadowCODE]

cout << "The square root of " << i << " is " << sqrt(i) << "." << endl
where is i coming from?

test.cpp: In function 'void print()':
test.cpp:27:35: error: 'i' was not declared in this scope

I think your function should be

void print(int i)
{
   cout << "The square root of " << i << " is " << sqrt(i) << "." << endl;
}

Dont forget to edit the declaration.

[jrt1990]

Now it says too few arguments in function call and 'print' function does not take 0 arguments.

[jrt1990]

Are you sure that's right?

[shadowCODE]

yes ofcourse, there is actually too few arguments if you call the function in main without its argument list.
Your call in line 15 should be print(i)

[jrt1990]

Lol oh boy now its telling me print function does not take 1 argument.

[jrt1990]

Ok nevermind I got it. Thank you so much for all of your help!

//Lab 3-1: Print out the values of square root of all 
//integers divisible by 5 between 5 and 100.

#include <iostream>
#include <math.h>
using namespace std;

void print(int i);

int main()
{

	for (int i = 5; i <= 100; i += 5){

		print(i);

	}

	cin.get();
	return 0;

}

void print(int i)
{

	cout << "The square root of " << i << " is " << sqrt(i) << "." << endl;

}