array size using pointer notation??

[dstewar4]

Is there a way to declare the size of an array using pointer notation without the square brackets that I used here?

const int SIZE = 100;
int myarray[SIZE];

[Duthomhas]

No.

[eker676]

What are you talking about exactly?

You can declare dynamically allocated arrays like this:

int arrayLength;

cout << "Enter array length: ";
cin >> arrayLength;

int* anArray = new int[arrayLength];

More on dynamically allocated objects:
http://www.cplusplus.com/doc/tutorial/dynamic/

[Bazzy]

If you don't want to use the square brackets you can use the C dynamic allocation:
int *myarray = (int*) malloc ( size*sizeof(int) );