Cash Register Program

[aSzG]

Hello, I am struggling on this part of my program. It says: You should have a function, let’s call it MakeSale(), that accepts no arguments and returns the total amount of the sale (including tax). All the input needed to make a sale should be requested from user inside MakeSale() function.


So far this is what I have. I am unsure how to return my total value so that it adds up the amount of items that the user has entered. Basically, I need "Item Price Tax: $" and "Price of Weighted Item: $" to add up within the MaleSale () function. Any suggestions would be helpful.

#include <iostream>

using namespace std;

// function prototype
double MakeSale();

int main()
{
	//Input 

	double total = 0;
	int count = 0;
	int choice = 1;

	while (choice != 0)
	{
		cout << "Welcome to Cash Register v2.0" << endl;
		cout << "=============================" << endl;
		cout << "1- New Sale" << endl;
		cout << "2- Cash In" << endl;
		cout << "3- Cash Out" << endl;
		cout << "4- Report" << endl;
		cout << "0- Exit" << endl;
		cout << "What do you want to do: ";
		cin >> choice;

		if (choice == 1)
		{
			int itemCount;
			cout << "How many items in this sale: ";
			cin >> itemCount;

			for (int i = 0; i < itemCount; i++)
			{
				int itemCode;
				cout << "Item Code: ";
				cin >> itemCode;

				if (itemCode < 100)
				{
					double itemPP;
					cout << "Item Price/Pound: ";
					cin >> itemPP;
					
					double itemWeight;
					cout << "Item Weight: ";
					cin >> itemWeight;

					double computeprice = itemPP * itemWeight;
					cout << "Price of Weighted Item: $" << computeprice << endl;
				}

				else
				{
					double itemPrice;
					cout << "Item Price: ";
					cin >> itemPrice;

					double Tax = itemPrice * 0.1;
					cout << "Item Price Tax: $" << Tax << endl;
				}

			}
		}

		else if (choice == 2)
		{
			double cash;
			cout << "Cash-in amount: ";
			cin >> cash;
			total = total + cash;
		}

		else if (choice == 3)
		{
			double cash;
			cout << "Cash-out amount: ";
			cin >> cash;
			total = total - cash;
		}

		else if (choice == 4)
		{

		}
	}
	system("PAUSE");
	return 0;
}

double MakeSale()
{

}

[crimsonzero2]

It sounds like what you do is just put what you have in choice == 1 into the function and have it return the price of all the items including the tax.

[aSzG]

That is what I am unsure how to do

[crimsonzero2]

So basically take all you have in choice == 1 and put it into the function. Then when the choice == 1, then call the function and have it equal to a double variable (since the function is returning a double). Then print out this variable like you originally have it at the end of choice == 1.

[aSzG]

Do you mean like this?

#include <iostream>

using namespace std;

// function prototype
double MakeSale(double);

int main()
{
	//Input 

	double total = 0;
	int count = 0;
	int choice = 1;

	while (choice != 0)
	{
		cout << "Welcome to Cash Register v2.0" << endl;
		cout << "=============================" << endl;
		cout << "1- New Sale" << endl;
		cout << "2- Cash In" << endl;
		cout << "3- Cash Out" << endl;
		cout << "4- Report" << endl;
		cout << "0- Exit" << endl;
		cout << "What do you want to do: ";
		cin >> choice;

		if (choice == 1)
		{
			MakeSale();
		}

		else if (choice == 2)
		{
			double cash;
			cout << "Cash-in amount: ";
			cin >> cash;
			total = total + cash;
		}

		else if (choice == 3)
		{
			double cash;
			cout << "Cash-out amount: ";
			cin >> cash;
			total = total - cash;
		}

		else if (choice == 4)
		{

		}
	}
	system("PAUSE");
	return 0;
}

double MakeSale(double)
{
	double total = 0;
	int itemCount;
	cout << "How many items in this sale: ";
	cin >> itemCount;

	for (int i = 0; i < itemCount; i++)
	{
		int itemCode;
		cout << "Item Code: ";
		cin >> itemCode;

		if (itemCode < 100)
		{
			double itemPP;
			cout << "Item Price/Pound: ";
			cin >> itemPP;

			double itemWeight;
			cout << "Item Weight: ";
			cin >> itemWeight;

			double computeprice = itemPP * itemWeight;
			cout << "Price of Weighted Item: $" << computeprice << endl;
		}

		else
		{
			double itemPrice;
			cout << "Item Price: ";
			cin >> itemPrice;

			double tax = itemPrice * 0.1;
			cout << "Item Price Tax: $" << tax << endl;
		}

	}
	return;
}

[crimsonzero2]

Mostly, you would want to return the total of the computeprice and tax in the return statement. Then you would want to use that by printing it out in a cout statement.

[aSzG]

Are we able to write return total = computetax + tax; ?

This is the first time returning something besides 0, sorry. :(

[crimsonzero2]

In a sense yeah. But you need the loop to keep track of all tax and computeprice to be able to be added into the returned total.