Output Memory Address As Binary?

[novellof]

#include <iostream>
#include <sstream>
#include <string>
using namespace std;

int main()
{
    int x = 5;
    
    cout << &x << endl; // output binary not hex...HOW??
    
    return 0;
}

please help

[48T7M4Gy]

If you want to convert hex to binary using C++ you'l have to write a small program/function. Google it and you'll find there are heaps of possibilities.

[troll warlord]

#include <iostream>
#include <bitset>

int main()
{
    using namespace std;
    
    int x = 5;
    
    cout << bitset<8*sizeof(int*)>(reinterpret_cast<long>(&x));
}

EDIT: I'm actually not quite sure about the cast; perhaps unsigned long is more appropriate ?

[novellof]

troll warlord ...you... are.... a.... god.... thank you!!!

please let me know how you knew how to do that!! thank you so much!

[48T7M4Gy]

Excellent!

[troll warlord]

Take a look at this reference: http://www.cplusplus.com/reference/bitset/bitset/

Although you should actually try to convert hex to binary (or any number system to binary interchangebly) using pure logic

[novellof]

thanks troll I already knew about bitset... I should have been more specific..How you casted a pointer to int and reinterpret cast ..

I would like to hear how you learned or knew to use those casts and stuff...

[troll warlord]

Messing around with this site really helped.

I also learned through this site:

http://en.cppreference.com/w/

[MiiNiPaa]

EDIT: I'm actually not quite sure about the cast; perhaps unsigned long is more appropriate ?

Both are technically wrong and would fail on Windows machine with 64bit addressing.

If you want to be really portable, use uintptr_t: http://en.cppreference.com/w/cpp/types/integer

[troll warlord]

I see, thanks!