The difference of 2 functions

[nooblet001]

Hello. What's the difference of this code:

	int pop()
	{
		int val = array[count];
		--count;
		val = array[count];
		return val;
	}

To this code:

	int pop()
	{
		--count;
		return array[count];
	}

How come the first function changes the value of the stack by simply returning a value?

[mutexe]

Line 3 in your first snippet doesn't do anything. when you realise this you can see they're the same. I think :)

[JackMorrill]

In line 3, you are just putting the contents of array[count] into the integer val and returning val instead of array[count].

[mutexe]

In line 3,

.. ignore line 3. Because in line 5 the value for 'val' get overwritten anyway.

[LB]

The difference is that one doesn't work, and the other almost works but gives in to the dark evil forces that add extra lines to people's code.

[mutexe]

but they do the same thing do they not?

[LB]

Unfortunately yes. It's just that the first one tried and failed whereas the second is simply wrong.