Explain the glitch
[sum=sum+j;]
1.semicolon shouldn't be put here but then if we put how do you explain the outcome?
2.Instead of [sum=sum+j, j++] we can also just put [sum += j++].
The comma operator is not need in the latter one..Why?
3.Please explain the difference b/w += and =+ operators.
[
//Sum of the first x natural numbers
#include <iostream>
using namespace std;
int main ()
{
int x, j(1), sum(0);
cout<<"Enter: \n";
cin>> x;
while (j<=x)
sum = sum+j; j++;
cout<<"Value: ="<<sum;
return 0;
}
]
1.semicolon shouldn't be put here but then if we put how do you explain the outcome?
2.Instead of [sum=sum+j, j++] we can also just put [sum += j++].
The comma operator is not need in the latter one..Why?
3.Please explain the difference b/w += and =+ operators.
[
//Sum of the first x natural numbers
#include <iostream>
using namespace std;
int main ()
{
int x, j(1), sum(0);
cout<<"Enter: \n";
cin>> x;
while (j<=x)
sum = sum+j; j++;
cout<<"Value: ="<<sum;
return 0;
}
]
Last edited on
| [sum=sum+j;] 1.semicolon shouldn't be put here but then if we put how do you explain the outcome? |
sum=sum+j; is a legal statement. [sum=sum+j;] is not. Is that what you're asking about?| The comma operator is not need in the latter one..Why? |
sum += j++ adds j to sum and then increments j.I like to use the for statement for loops like this. It makes it clear what you're looping through vs. what you're doing in each iteration of the loop:
|
|
Hi dhayden! (:
I've put square brackets just to differentiate that it's a code.
Anyway what I was asking is the difference b/w
sum = sum+j, j++ //By which sum of the natural no. program can run.
sum=sum+j; j++ //A different outcome because of ; operator.How does the compiler interprets the code this time?
Yea..for loops provides specific locations for the input unlike while but then I was asked to do with while loop only.
Ps: I'm just a beginner.So I wrote in a layman language instead of technical ones.Please don't mind.Have a nice day!
I've put square brackets just to differentiate that it's a code.
Anyway what I was asking is the difference b/w
sum = sum+j, j++ //By which sum of the natural no. program can run.
sum=sum+j; j++ //A different outcome because of ; operator.How does the compiler interprets the code this time?
Yea..for loops provides specific locations for the input unlike while but then I was asked to do with while loop only.
Ps: I'm just a beginner.So I wrote in a layman language instead of technical ones.Please don't mind.Have a nice day!
Last edited on
Please use code tags to highlight code.
The differenence is that
I've found the comma operator handy in
The differenence is that
sum = sum+j,j++ is an expression. It's value is the value of the right hand side of the comma operator. You could assign it to another value: x = (sum = sum+j,j++) is equivalent to |
|
I've found the comma operator handy in
for loops (there I go again!) e.g. to walk a linked list and count the items at the same time:for (node = top, count=0; node; node=node->next,++count)
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