Macro to Function

[Luciano Rezende]

Hi friends, I'm facing some difficulties to translate this macro to a function, take a look:

#define EXPSIZE 2000
extern double neglibleExp;

#define ApprExpProb(R) ((R) > neglibleExp ? \
	0.0 : exps[(int) ((R) / neglibleExp * EXPSIZE + 0.5)])
// exps is a global vector of doubles 

to

 double ApprExpProb (double R) {
  if (R > neglibleExp) {
     // ?
  }
}

What means that "\" character in the macro?
Can anybody give a hand? Thank you!

[MiiNiPaa]

\ at the end of line means that line break should be ignored.

So you can do:

double ApprExpProb (double R) {
  if (R > neglibleExp) {
    return 0;
  } else {
    return exps[(int) ((R) / neglibleExp * EXPSIZE + 0.5)];
  }
}

or, without eliminating ternary operator

double ApprExpProb (double R) {
  return (R) > neglibleExp ? 0.0 : exps[(int) ((R) / neglibleExp * EXPSIZE + 0.5)];
}

[Luciano Rezende]

Perfect!