c++ array code explain

[mycoding]

Hello there, could some one explain the following array code, knowing i am new to the language.
mostly do not grasp code in line 15
15 for ( int i = 0; i < 10; ++i ), why he uses it, and is this effect final result j. plz explain.

1 // Fig. 7.4: fig07_04.cpp
2 // Initializing an array in a declaration.
3 #include <iostream>
4 #include <iomanip>
5 using namespace std;
6
7 int main()
8 {
9 // use initializer list to initialize array n
10 int n[ 10 ] = { 32, 27, 64, 18, 95, 14, 90, 70, 60, 37 };
11
12 cout << "Element" << setw( 13 ) << "Value" << endl;
13
14 // output each array element's value
15 for ( int i = 0; i < 10; ++i )
16 cout << setw( 7 ) << i << setw( 13 ) << n[ i ] << endl;
17 } // end main 

results:

Element Value
0 32
1 27
2 64
3 18
4 95
5 14
6 90
7 70
8 60
9 37

[wildblue]

The array n has 10 elements, so the valid index values for the array will run from 0 to 9 (total size minus 1). The for loop on line 15 prints out the current value of the index (variable i) and the value of the array at that index - it starts at 0 and runs up to 9.

Does that make sense?

[j3Rz8vqX]

wildblue has already provided a good answer, I am simply extending information:
int n[ 10 ] = { 32, 27, 64, 18, 95, 14, 90, 70, 60, 37 };
is equivalent to:

int n[10];

n[0]=32;//1
n[1]=27;//2
n[2]=64'//3
//...
n[8]=60;//9
n[9]=37;//10 

Arrays start count from 0, so an array of 10 would have indexes 0-9 (10 indexes).

Line 15, is a for_loop that has localized an integer variable of i=0, will repeat while i is less than 10, and will increment by 1 at the end of every cycle. The code it encapsulate would be a print out of i and the array value at index i.