Pointer to member of derived type

[z0My6Up4]

My compiler throws an error cannot convert a pointer to a member of a derived type to a pointer to a member of it's base type:

class B{ };
class D : public B { }

class Foo
{
...
public:
	D member;
};

B Foo:: * pm = &Foo::member; // error, can't convert to B Foo::* 

Please can anyone explain why this is a problem & how I can work around it?
Thanks

[codewalker]

I dont get what you are achieving by B Foo:: * pm = &Foo::member;

If you want to declare pointer to B then B *pm is the code.

And you cant just use scope resolution operator to get pointer to a member, you need to allocate memory/construct and object the class.

Foo f;
B *pm = &(f.member);

is the code if I have got what you want to achieve.

[Cubbi]

There is no member of Foo (or Foo's base) that has type B. A pointer of type B Foo::* cannot be valid.

What are you trying to work around? Perhaps you simply needed Foo foo; B* pm = &foo.member?

[z0My6Up4]

thanks