Bytes of stored words.

[rshoe]

I have a char array with three words and I am trying to find out how many bytes are necessary to store the actual 3 words of data stored in the array. If anyone can help me I would appreciate it. I think you use sizeof() but I am not sure.

Thanks,
R.

Here is my char array code:

  char words[3][9] = {"Zinc", "Artifact", "Zilch"};

[MiiNiPaa]

Minimum amount of bytes you can fit all three words?

It will be length of all words + count of words: 1 byte per character + 1 byte per word for trailing 0.

[JockX]

You are better off using strlen: http://www.cplusplus.com/reference/cstring/strlen/

1 2 3 4

char words[100] = "Zinc"; int i = strlen(words); int j = sizeof(words); std::cout << i << " " << j;

4 100

[rshoe]

Thanks everyone for your information. This helps me a lot.

Thanks!
r.