Question about If, Else statements

[bigorangeman]

Write a program that accepts two numbers – temperature and day of week (if it is Sunday 1, otherwise 2. Display the following, if:

temperature < -10 and Sunday – Stay home.

temperature < -10 and not Sunday – Stay home, but call work.

temperature <= 0 (but >= -10) – Dress warm.

temperature > 0 and Sunday – Play hard.

temperature > 0 and not Sunday – Work hard.

Hint: Use if and else if statements

*** Sample output

Please enter temperature: .5

Is it Sunday(Yes=1, No=2)? 1

Play hard.

Please enter temperature: -8

Is it Sunday(Yes=1, No=2)? 2

Dress warm.

Ok sorry guys I am a complete noobie, but here is my question that I am struggling with. It seems like I have got it mostly right, but when I try to input .5 it completely skips me being able to input the day of the week and just outputs work hard. I can put in a whole number and it seems to work fine. Is there something in particular I am missing here?

#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
    
    int temperature;
    char weekday;

  

   cout << "Please enter temperature: ";
   cin >> temperature;
   
   cout << "\n";

   cout << "Is it Sunday(Yes=1, No=2)? ";
   cin >> weekday;
   
   cout << "\n";
   
   if ((temperature < -10) && (weekday == 1)) {
                    cout << "Stay home" << endl;
       
   }else if ((temperature < -10) && (weekday != 1)) {
          cout << "Stay home, but call work" << endl;
       
   }else if ((temperature <= 0) && (temperature >= -10)) {
          cout << "Dress warm" << endl;
       
   }else if ((temperature > 0) && (weekday == 1)){ 
           cout << "Play hard" << endl;
           
   }else if ((temperature > 0) && (weekday != 1)) {
       cout << "Work hard" << endl;
       }
       
    system("PAUSE");
    return EXIT_SUCCESS;

}

[wildblue]

You've defined temperature as an int. Sounds like you should be defining it as a floating point type (float or double) if temperatures with decimals are going to be entered?

[Chervil]

Since you are inputting .5 as the temperature, the variable temperature cannot be of type int. Use double instead to allow the input of decimal values.


In the comparison (weekday == 1) weekday is a char but 1 is an integer. You should compare like with like, or at least types which are readily convertible. In this case, use the character '1' instead of the integer 1, that is, (weekday == '1')

[bigorangeman]

Awesome, that looks like it should take care of it. Thank you all sooo much.