question about adding two fractions

[uzipaz]

Hey all, I am new in learning the C++ language..
I have question about the program for adding two fractions..

Here is my code:
// adding two fractions

#include <iostream>
using namespace std;

int main()
{
float a;
float b;
float x;
float y;

// input

cout << "Enter numerator value of First fraction" << endl;
cin >> a;
cout << "Enter denominator value of First fraction" << endl;
cin >> b;

cout << "Enter numerator value of Second fraction" << endl;
cin >> x;
cout << "Enter denominator value of Second fraction" << endl;
cin >> y;



// Process

cout << "The Result is " << (a/b)+(x/y) << endl;

return 0;
}

The answer is given to me in decimal (when the fraction is added).. but i want it to give me the answer the fraction form.. I cant help it doing that..
We know that fractions like 2.25, 1.5, 1.25 are rational fractions so they can be converted in rational numbers like ( 4/1, 3/2 etc.. )
So, tell me a technique to do this..

thanks..

[smilodon]

Why are storing integers as floats?

Also, can you write an example of how you would like to see the fraction formatted?

Third, I didn't know there was the program for storing fractions.

Fourth, if you want to really impress your teacher, use classes.

Finally, use code tags. [co de][/c ode] without the spaces.

[helios]

Why are storing integers as floats?

Fractional fractions. Duh. :-)

Fourth, if you want to really impress your teacher, use classes.

Quiet, you.

The best way is to not compute the decimal floating point representation in the first place.
Instead of outputting a/b+x/y, output separately a*y+x*b and b*y. The result will not be simplified (for example, it could give 2/2, rather than 1/1).


a c a * d + c * b
--- + --- = ---------------
b d b * d

[smilodon]

Well, then he could use operator overloading.