Tic Tac Toe game help

Hello there,

first of all thank you for taking your time to open this topic and trying to help me, I really appreciate it.

Alright, so the thing is that I have this code and I don't know how to finish it.

I need help finishin the last part of the problem where it says "returns the player ('X' or 'O') if the game has been won", notice that there is one example already done but i dont know how to finish the rest.

I already finished most of the code that i needed to finish, but I can't figure out how to finish the last part.

I would really appreciate if someone could help me finish it.

Thank you!

#include "stdafx.h" // Only for Microsoft Visual C++
#include <iostream> // needed for cin and cout
#include <cstdlib>  // needed by srand() and srand()
#include <ctime>    // needed for the time() function
using namespace std;

// function prototypes
void DisplayTicTacToe(char board[3][3]);
char CheckForWinningGame(char board[3][3]);

int main(int argc, char* argv[])
{
    char board[3][3] = {    // index for positions in the array
    {'1', '2', '3'},        //  [0][0]  [0][1]  [0][2]
    {'4', '5', '6'},        //  [1][0]  [1][1]  [1][2]
    {'7', '8', '9'}         //  [2][0]  [2][1]  [2][2]
    };

    int  squareCounter = 0; // count how many squares are used
    char gameWinner = '-';  // winner of the game ('X' or 'O')
    char inputCharacter;    // input from the user (should be '1' to '9')
    int  choice;            // input converted to integer 0 to 8 (start from 0)
    char player;            // current player, set to either an 'X' or an 'O'

    // select the starting player
    srand(time(NULL));         // seed the random number generator
    if ( rand() % 2 == 1)
        player = 'X';
    else
        player = 'O';

    // starting instructions
    cout << "Enter a 1 though 9  to select a square." << endl;

    // Ask for a 1-9 until all squares are filled or the game has been won
    while (squareCounter < 9 && gameWinner != 'X' && gameWinner != 'O')
    {
        DisplayTicTacToe(board);
        cout << "Player " << player << ", enter a number (1-9): ";
        cin  >> inputCharacter;

        // Arrays start counting from index 0
        // convert inputCharacter from ASCII ('1' to '9') to integer (0 to 8)
        // to select the row and column index for the 3x3 array
        choice = inputCharacter - '1'; // now the inputs are 0,1,2,3,4,5,6,7,8
        int row = choice / 3; // row will be 0 (for 0,1,2), 1 (for 3,4,5), 2 for (6,7,8)
        int col = choice % 3; // col will be 0 (for 0,3,6), 1 (for 1,4,7), 2 for (2,5,8)

        if (choice < 0 || choice > 8)   // see if the input is below 1 or greater than 0
            cout << "Illegal value, try again" << endl;
        else if (board[row][col]=='X' || board[row][col]=='O')
            cout << "This space has already been used, try again" << endl;
        else
        {
            board[row][col] = player;   // put in an 'X' or an 'O'
            squareCounter++;            // count the number of squares completed
            // select the next player
            if (player=='X')            
                player = 'O';           // switch from 'X' to 'O' for next move
            else
                player = 'X';           // switch from 'O' to 'X' for next move
        }
        gameWinner = CheckForWinningGame(board); // returns 'X' or 'O' if the game is won
    }
    if (squareCounter == 9)
    {
        DisplayTicTacToe(board);
        cout << endl << "Tie Game" << endl << endl;
    }
    else if (gameWinner =='X' || gameWinner == 'O')
    {
        DisplayTicTacToe(board);
        cout << endl << "Player " << gameWinner << " wins the game" << endl << endl;
    }
	return 0;
}

// ------ Display the Tic Tac Toe board
void DisplayTicTacToe(char board[3][3])
{
    cout << endl;
    for (int row=0; row<3; row++)         // display three rows
    {
        for (int col=0; col<3; col++)     // display three columns each row
            cout << board[row][col] << ' ';    
        cout << endl;                     // end of row
    }
    cout << "--------------------------------" << endl << endl;;
}

// ------ See if the game has been won
//  returns the player ('X' or 'O') if the game has been won
char CheckForWinningGame(char board[3][3])
{
    char player;

    // check going across the top row to see if all squares are the same
    player = board[0][0];
    if (board[0][1] == player && board[0][2] == player) return player;

    // check going across the middle row to see if all squares are the same

    // check going across the bottom row to see if all squares are the same

    // check going across the first column to see if all squares are the same

    // check going across the second column to see if all squares are the same

    // check going across the third column to see if all squares are the same

    // check going down the left diagonal \ to see if all squares are the same

    // check going down the right diagonal / to see if all squares are the same

    return '-';     // if there is no winner
}

Last edited on

dhayden (5798)

Look closely at the code that checks if the top row is all the same:

1
2

    player = board[0][0];
    if (board[0][1] == player && board[0][2] == player) return player;

This sets "player" equal to the value in the top left. The "if" statement then checks if the other two squares in the top row are the same as the top left one. If they are, it returns the value of the top left square.

Note that there's actually a bug here: if all three squares are '-' then it will return, which means it won't check the other possibilities

Once you get the code right for the first case, the other cases are basically the same, only you need to check other squares in the board by changing the indexes that you check.

Hope this helps.
Dave

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