Do integral sum

[EwCjE3v7]

Exercise:

Assuming i is an int and d is a double, write the expression i *= d so that it does integral, rather than floating-point multiplycation

This is what I got

    int i = 5;
    double d = 4.25;
    int sum = static_cast<int>(i) * d;

    cout << sum << endl;

But I think I`m wrong

[LB]

i is already an int, there is no reason to cast it to an int. Both operands to the multiplication operator must be integral to perform integral multiplication. You're very close! By the way, you should name the result variable product and not sum.

[EwCjE3v7]

Thank you LB, so there is no way to do a integral sum? Because what i *= d does is that it multiplies them and return 21.25.

Wouldn`t this work?

int i = 5;
    double d = 4.25;
    i *= static_cast<int>(d); // does 5 * 4
    cout << i << endl; // output is 20 

[LB]

The assignment you quoted asks for integral multiplication, not integral sum.