Max of Numbers

[RobGillespie]

So I have a simple problem that I've been working on and I'm having some scope issues. My program is supposed to have the user input how many numbers he/she wants to enter and then let the user enter an initial number so that I can hold the max value. Then the for loop starts and attempts to store the maximum number throughout the loop. The problem I have is that at the end of the loop when I want to pull the max number out, I can't because of the variables within the loop are gone once the loop ends. How do I pull the "max" out of the loop and output it for a final answer? Here is my code:

#include <iostream>
using namespace std;

int main()
{
	cout << "This program finds the maximum number." << endl << endl;

	int amount;
	cout << "How many numbers? ";
	cin >> amount;

	float number, max;
	cout << "Number: ";
	cin >> number;

	max = number;

	for( float i = 0; i < (amount - 1); i++ )
	{
		float number;
		cout << "Number: ";
		cin >> number;

		if(max > number)
			max = number;
		else
			number = max;
	}
	cout << "The largest number is " << max;
}

If you run the code you can see that when I first set a value to "max" it stays that value that is outside of the loop. The max inside the loop simply does nothing. What do I do to get "max" to change in the loop and then call that "max" outside of the loop to use it as output?

[Null]

Line 24 is wrong. You are checking if max is less than the number you enter. Correct code:

		if(max < number) // read: if max is less than number,then max =number
			max = number;
// 'else' statement is not needed. it doesn't do anything useful 

[RobGillespie]

Ok so you can pull a variable out of the scope of the loop I just had the wrong condition. Thank you.