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delete the last and first line in an interval

dero (38)
hey all
well I have been facing this problem for days and I don't seem to get an answer to it. I have written a code where my program is suppose to read specific number of lines within different ranges and then count the number of occurrence of r and s and divide the r by the s. here's a snap shot of my trace file I am working on 


s 167.204369958 _7_ MAC  --- 29867 tcp 630 [13a 8 7 800] ------- [7:2 8:1 32 8] [330 0] 0 1..
r 167.209410087 _8_ MAC  --- 29867 tcp 572 [13a 8 7 800] ------- [7:2 8:1 32 8] [330 0] 1 1..
s 167.212674795 _7_ MAC  --- 29868 tcp 630 [13a 8 7 800] ------- [7:2 8:1 32 8] [331 0] 0 1..
r 167.217714923 _8_ MAC  --- 29868 tcp 572 [13a 8 7 800] ------- [7:2 8:1 32 8] [331 0] 1 1..
D 167.240723594 _8_ MAC  BSY 0 RTS 44 [162e 8 7 0] ..
D 167.243783594 _8_ MAC  BSY 0 RTS 44 [162e 8 7 0] ..
s 169.998902881 _7_ MAC  --- 30344 tcp 630 [13a 8 7 800] ------- [7:3 9:0 32 8] [147 0] 0 1..
r 170.003942963 _8_ MAC  --- 30344 tcp 572 [13a 8 7 800] ------- [7:3 9:0 32 8] [147 0] 1 1..
s 170.162989092 _7_ MAC  --- 30466 tcp 630 [13a 8 7 800] ------- [7:2 8:1 32 8] [334 0] 0 1..
r 170.168029172 _8_ MAC  --- 30466 tcp 572 [13a 8 7 800] ------- [7:2 8:1 32 8] [334 0] 1 1..
s 170.181482383 _7_ MAC  --- 30467 tcp 630 [13a 8 7 800] ------- [7:2 8:1 32 8] [335 0] 0 1..
r 170.186522463 _8_ MAC  --- 30467 tcp 572 [13a 8 7 800] ------- [7:2 8:1 32 8] [335 0] 1 1..
s 178.013133357 _7_ MAC  --- 32131 tcp 630 [13a 8 7 800] ------- [7:2 8:1 32 8] [340 0] 0 1..
r 180.725285180 _8_ MAC  --- 32716 tcp 572 [13a 8 7 800] ------- [7:2 8:1 32 8] [341 0] 1 1..

The program is running correctly but the problem takes place in such cases 

s 169.998902881 _7_ MAC  --- 30344 tcp 630 [13a 8 7 800] ------- [7:3 9:0 32 8] [147 0] 0 1..
r 170.003942963 _8_ MAC  --- 30344 tcp 572 [13a 8 7 800] ------- [7:3 9:0 32 8] [147 0] 1 1..

where the s line is at the end of interval and the r line is received at the beginning of the second interval ...giving incorrect counting because in the second interval the received line will be greater than the send lines which gives a % higher than 100 which is incorrect.
I thought about checking if the s is followed by r within the interval if not delete the line and another check was to check for the sequence number which is this number 30344 this number should be equal for each r-s pair

here's my code 


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  #include <iostream>
#include <fstream>
#include <iomanip>
#include <cmath>
#include <string>
#include <sstream>
#include <vector>

    using namespace std;

int main()
{
    ofstream fout("TPDR[3-4-30].tr");
    ifstream fin("TTEST.tr");// if u use this as ur input file u will always get ur num as 6 because the range stops at 50 therefore u will get the throughputs calculated as 0z 
    ofstream fOut("TPDR30(3-4).tr");
    ofstream MYFILE("TPDR(3-4).tr");
    
    if (!fin)
    {
        cout << "input file not open" << endl;
        return 1;
    }

    fout << fixed << setprecision(9);
    fOut << fixed << setprecision(9);
    cout << fixed << setprecision(9);
    MYFILE << fixed << setprecision(9);

    double timelimit = 0.0;    // ending time of first block of data
    double timeincr  = 10.0;   // duration of each block of data

    string s1, s2, s3, sequenceno1,sequenceno2, s4, s5; // dummy variables to hold unwanted data 
    string line,oldline;
    
    char   type;   
    double time;   
    int    bytes;  
    int num = 0;
    istringstream ss;
    double received[21] = {0.0}; 
    double send[21] = {0.0}; 
    int drop[21] = {0}; 
    double Re[21]= {0.0};
    double Se[21] = {0.0};
    double De[21] = {0.0};
     int R = 0;
     int S = 0;
    double PDR =0.0;
    double PDRR[21] = {0.0};
    int Range; 
   
     
    //------- Priming read. Get first line.
    getline(fin, line);
    ss.str(line);
    ss >> type >> time;

    while (fin)
    {
        while (ss && time <= timelimit)
        {
			 
            //------------- process the line here ------------------
                 // ss >> s1 >> s2  >> s3 >> s4 >> s5 ;
                   
                             
                                
         if (type == 's') {
									  
		          ss >> s1 >> s2 >> s3 >> sequenceno1 >> s4 >> s5;
					  oldline = line;
					  send[num]++; 
					  S = send[num]; 
					  Se[num] = S; 
				  }
					  
					                  
               if (type =='r') {
					
					  ss >> s1 >> s2 >> s3 >> sequenceno2 >> s4 >> s5;
				  if ((time < timelimit)&&(sequenceno1 == sequenceno2)) {
					  cout << sequenceno1 << "   " << sequenceno2 << "    " << time << "    " << timelimit << ".\n";
				     received[num]++;
					 R = received[num];
					 Re[num] = R;
					 PDR = Re[num]/ Se[num];
					 PDRR[num] = PDR*100;
	
	fout << "Received = " << Re[num] <<"     " << time <<"    " << "Send= " << Se[num] << "  " << "Packet Delivery Ratio" << PDRR[num]  << "    "<< "sequenceno1 =" << sequenceno1 << "      "<< "sequenceno2 ="  << sequenceno2 << ".\n"; 
		
		
                }
        
                }
         
            //------------- end of process, now read the next line -----

            if (getline(fin, line))
            {
                ss.clear();             // clear all flags
                ss.str(line);
                ss >> type >> time;
            }
            else
            {
                ss.clear(ios::failbit); // set the fail flag
         
            }
            
        }
        
        

        timelimit += timeincr; // increment limit to next value
        cout << timelimit << ".\n\n";
        num++; 
        fout << "\n------------------\n";
        fout << "time limit: " << timelimit << endl;
        cout << "num = " << num << ".\n";
    } 
    
   // ..... Writting the Range and PDR within each Range in a separate File .....
   
for (Range = 10,num =1; Range <= 200, num <=20; Range+=10, num++) {
	fOut << Range << "     " << PDRR[num] << ".\n";
 } 
 
 double average = 0.0;
 double TPDR = 0.0;
 
 for (num = 1; num <=20 ; num++) {   // For loop to compute the Total PDR within each Range 
	 TPDR += PDRR[num]; 
	// cout << "TPDR" << TPDR << "%" << ".\n"; 
 }
 
 average = TPDR /(num-1);
 cout << "average = " << average << "%" <<  ".\n";// Compute Average PDR 
 
    cout << "Done" << endl;
    return 0;
}


here's the output 


time limit: 180.000000000
r 170.003942963 _8_ MAC  --- 30344 tcp 572 [13a 8 7 800] ------- [7:3 9:0 32 8] [147 0] 1 1...
s 169.998902881 _7_ MAC  --- 30344 tcp 630 [13a 8 7 800] ------- [7:3 9:0 32 8] [147 0] 0 1...

don't know y is it comparing with the s from previous interval ?
Not logic output 

Received = 1.000000000     170.003942963    Send= 0.000000000  Packet Delivery Ratioinf    sequenceno1 =30344      sequenceno2 =30344.

plz help me out
dero (38)
@chervil can u plz help me out
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