Scanning the number of letters and numbers in a string

[AnimasterCH]

Hello,

I have an assignment to write a code that will ask for a licence plate and in return will answer whether it is a regular, a custom or incorrect. Since I live in Estonia, where regular plates are 3 or 2 numbers followed by 3 letters and custom plates have up to 9 characters where there has to be atleast 1 number and 1 letter.

What I am having trouble with is: How can i make the program count the numbers and letters separetly from a line?

For example i ask for a licence plate and the user enters 851TFF and it should understand that it's a regular and give the respective answer, but if something random is inserted or it goes over the limit like 854 then it would say that it is invalid.

Thanks in advance,
Christo

[MiiNiPaa]

Do you need something like:

std::string line;
std::cin >> line;
int digits = 0;
int letters = 0;
int other = 0;
for(char c: line) {
         if(isdigit(c))
        ++digits;
    else if(isalpha(c))
        ++letters;
    else
        ++other;
}
if (other != 0)
    std::cout << "junk symbols in plate number";

[iAk3T05o]

@minipaa: could you explain your code?

[MiiNiPaa]

std::string line; //Declare variable called line of type of std::string
std::cin >> line;  //Read input from user into line variable
int digits = 0;  //Create counters
int letters = 0; //For different kind
int other = 0;   // of symbors
for(char c: line) { //Loop for each symbol in line
         if(isdigit(c)) //If currend symbol is a digit...
        ++digits; //...increase number of digits
    else if(isalpha(c)) //If it is a letter...
        ++letters; //Increase amount of letters
    else //If it is not a digit or a letter
        ++other; //Then it is some other symbol
}
//Now in digits variable we have amount of digits, number of letters in letters, and other symbols in other
if (other != 0) //Output message if there is anything aside from digits and letters in entered License Pate
    std::cout << "junk symbols in plate number";