CODE OPTIMIZATION
Feb 7, 2014 at 1:39pm UTC
Please, can you take a look at this poorly written code and highlight the problems in it, in order to achieve optimal run time i.e. reduce run time as much a possible. The code will output a file "data_out". you will need to run it once and then confirm that "data_out_new" is exactly the same. Please if this task is unclear, let me know.
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#include <iostream>
#include <fstream>
#include <math.h>
using namespace std;
int main(int argc, char * argv[]) {
int nx(10000);
int ny(200);
int nt(200);
double ** vi=new double *[nx];
double ** vr=new double *[nx];
double pi=(4.*atan(1.));
for (int i=0;i<nx;i++) {
vi[i]=new double [ny];
vr[i]=new double [ny];
}
for (int i=0;i<nx;i++) {
for (int j=0;j<ny;j++) {
vi[i][j]=double (i*i)*double (j)*sin(pi/double (nx)*double (i));
vr[i][j]=0.;
}
}
ofstream fout("data_out" ) ; // change to data_out_new and check!
for (int t=0;t<nt;t++) {
cout<<"\n" <<t;cout.flush();
for (int i=0;i<nx;i++) {
for (int j=0;j<ny;j++) {
if (i>0&&i<nx-1&&j>0&&j<ny-1) {
vr[i][j]=(vi[i+1][j]+vi[i-1][j]+vi[i][j-1]+vi[i][j+1])/4.;
} else if (i==0&&i<nx-1&&j>0&&j<ny-1) {
vr[i][j]=(vi[i+1][j]+10.+vi[i][j-1]+vi[i][j+1])/4.;
} else if (i>0&&i==nx-1&&j>0&&j<ny-1) {
vr[i][j]=(5.+vi[i-1][j]+vi[i][j-1]+vi[i][j+1])/4.;
} else if (i>0&&i<nx-1&&j==0&&j<ny-1) {
vr[i][j]=(vi[i+1][j]+vi[i-1][j]+15.45+vi[i][j+1])/4.;
} else if (i>0&&i<nx-1&&j>0&&j==ny-1) {
vr[i][j]=(vi[i+1][j]+vi[i-1][j]+vi[i][j-1]-6.7)/4.;
}
}
}
for (int i=0;i<nx;i++) {
for (int j=0;j<ny;j++) {
if (fabs(fabs(vr[i][j])-fabs(vi[i][j]))<1e-2) fout<<"\n" <<t<<" " <<i<<" " <<j<<" " <<fabs(vi[i][j])<<" " <<fabs(vr[i][j]);
}
}
for (int i=0;i<nx;i++) {
for (int j=0;j<ny;j++) vi[i][j]=vi[i][j]/2.+vr[i][j]/2.;
}
}
}
Feb 7, 2014 at 2:28pm UTC
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