get method prints only first letter in char array..why??

[alsade]

Header:

class employee
{
	int* id;
	char* name;
	int daysNotPaid;
	bank mybank;
	int accountnum;
	int* datebirth;
	double balance;
public:
	employee();
	employee(int idnum ,char*);
	int getid();
	char* getname();
	int getdaysnotpaid();
	bank getbank();
	int getdate();
	int getaccnum();
	double getbalance();
	void setid(int);
	void setdays(int);
	void setbank(bank);
	void setaccountnum(int);
	void setdatebirth(int);
	void setbalance(double);
	void work();
	void printpersoninfo();
	void payment();
	bool performshopping(int);
	int getage(int);
	~employee();
};

cpp:

#include <iostream>
#include <cstring>
#include <string>
#include "Employee.h"

using namespace std;


employee::employee()
{
	id=new int[9];
	datebirth=new int[8];
}

employee::employee(int idnum,char* ename)
{
	id=new int [9];
    *id=idnum;
	this->name=ename;
	datebirth=new int[8];
}

int employee::getid()
{
	return *id;
}

char* employee::getname()
{
	return name;
}

main:

#include <iostream>
#include <string>
#include "Employee.h"

using namespace std;

int main()
{
	int emp1id;
	char emp1name[30];
	cout<<"employee #1 name: ";
	cin>>emp1name;
	cout<<"employee #1 id: ";
	cin>>emp1id;
	employee emp1(emp1id,emp1name);
}

why when im trying to print the employee's name like this:
cout<<"Name: "<<*name<<endl;
it prints only the first letter?

[TwilightSpectre]

That is because saying *name is actually dereferencing the pointer you passed, which is the same as writing *(name+0) or name[0], which gives as a char value the first character. Try just doing this instead: std::cout << "Name: " << name << std::endl;