file.open(..); string parameter

[TheSte]

Hi all,

I've been making this program for a training but I've found this problem...

whem I use file.open I want to name the file with the content of a string variable..
for example

string name = "text";

file.open(name + ".txt");

Visual C++ say that the variable can't be a string-type...How to solve it?

Thanks in advance and sorry for my English but I'm 15 and I'm Italian

[Bazzy]

file.open ( ( name + ".txt" ).c_str() );
.c_str() converts C++ strings in C strings