pi out of function value

[enemy]

Hello!
In this example, variable pi is declared out of the function value, but in the same namespace.

Is it authomatically entering the function then?

Many thanks!

  // namespaces
#include <iostream>
using namespace std;

namespace foo
{
  int value() { return 5; }
}

namespace bar
{
  const double pi = 3.1416;
  double value() { return 2*pi; }
}

int main () {
  cout << foo::value() << '\n';
  cout << bar::value() << '\n';
  cout << bar::pi << '\n';
  return 0;
}

[Glandy]

It should be globally accessible within the namespace. (yes)
Why don't you just try it out ;)

[enemy]

Thanks, that's it!