Code not working.

[rlrmorris21]

Nothing pops up after I type in length. Any advice?(This code is a WIP)

  #include <iostream>
using namespace std;
char type1[26];
c



int main()
{
    cout << "Please choose length, tempature, or money contverters! Type exit to quit!" << endl;
    cin >> type1;
    if(type1=="length"){
        cout << "What measurements you like converted?";
    }
    

}

[LB]

There is a syntax error caused by line 4.

On line 12 you are comparing the address of the array to the address of the c-style string literal - I can guarantee they will never be the same.

If you are going to use C++, use std::string and stop pretending you are using 'C with Classes'.

[j3Rz8vqX]

What Lb meant:

type1[26] == "length--------------------";//possibly garbage; editor doesn't like spaces.

So, type1 == "length", would never be the same.

Therefore you would receive no print outs because it would never pass the if_condition test.

His advice was to redesign using std::string; string has a dynamic size, so if it should not have extended garbage.

Otherwise, your alternative is to compare characters inside the character array to see if a match was found - possibly the first 6 characters and ensure consecutive order.

Have fun.

Edited: Forget what I said. LB stands correct:

warning: comparison with string literal results in unspecified behaviour [-Waddress]

[LB]

Dput wrote:

What Lb meant:

type1[26] == "length--------------------";//possibly garbage; editor doesn't like spaces.

I have absolutely no idea what you mean, but it is definitely not what I meant. When you compare an array and a string literal, you compare the addresses.