Validating user input

[bookLearnin]

Hello, I am in the process of learning about validating input so that when the user types in a word instead of an integer, the program doesn't crash. This is a small piece of code that will validate the scenario mentioned above but with one problem. Whenever I actually type in a valid number ex: 123, directly after starting the program, I will have to type it twice for the function to accept it. Does anyone know why this is?

#include <iostream>
using namespace std;
int validate(int);
int main()
{
	int integer;
	cout << "enter a number\n";
	cin >> integer;
	integer = validate(integer);
}


int validate(int number)
{
	bool failed;
	do
	{
		cin.clear();
		if (cin >> number && number > 0)
		{
			cout << "value entered: " << number << endl;
			failed = false;
		}
		else
		{
			failed = true;
			cout << "You must enter a positive integer." << endl;
			cin.clear();
			cin.ignore(numeric_limits<streamsize>::max(), '\n');
		}
		cout << endl;
	} while (failed == true || number <= 0);
	return number;

}

[cwr2k]

Because you're asking for input twice.

#include <iostream>
using namespace std;
int validate(int);
int main()
{
	int integer;
	cout << "enter a number\n";
	cin >> integer;                              // <---- Once here.
	integer = validate(integer);
}


int validate(int number)
{
	bool failed;
	do
	{
		cin.clear();
		if (cin >> number && number > 0)   // <---- And once here
		{
			cout << "value entered: " << number << endl;
			failed = false;
		}
		else
		{
			failed = true;
			cout << "You must enter a positive integer." << endl;
			cin.clear();
			cin.ignore(numeric_limits<streamsize>::max(), '\n');
		}
		cout << endl;
	} while (failed == true || number <= 0);
	return number;

}

[bookLearnin]

lol wow, can't believe I didn't catch that, Thanks!