Copy constructor woes

[Joe101]

can someone tell me why the copy constructor does not seem to be called when the code below is run?

class Person{
    public:
        Person(string * n){
            name = new string(*n);
            }

//Copy constructor
    Person(const Person &p){
    cout <<"copy constructor called"<<endl;
        name = new string(*p.name);

        }

~Person(){
        delete name;
    }

protected:
        string * name;
};



int main(){

string s1 ="Jimmy Bob";
string *ps = &s1;
Person p1(ps);

s1="voodoo";
ps = &s1;
Person p2(ps);
//WHY DOESN"T NEXT LINE CAUSE COPY CONSTRUCTOR TO BE CALLED?
p2 = p1;
}

[Dufresne]

You don't use copy - constructor there. You use assignment operator.
There are 2 ways to use copy constructor , that i know.
First way ;

Person p2 = p1 ;

second way ;

Person p2( p1 );

NOTE THAT

Person p2 = p1 ;

and

Person p2 ;
p2 = p1 ;

are different.

[Bazzy]

That line calls the assignment operator ( = ).
Copy constructor is called on initialization: Person p2 = p1;

[Joe101]

thanks!