soting..

[Cutefriendzoned]

Hey guys I got two questions , please anser , what's the difference between when a function takes a variable with * " pointer " , like this :
void function(int *x);
int y;
function (y);

and what's the difference between this and & " ref "

also I want trying to sort an array from min to max using a sorting algorithm

here's the code , what's wrong with it ? it shows 3 3 6 6

  #include <iostream>
#include <iomanip>
using namespace std;



int main()
{

	const int size = 5;
	int x[size] {5, 3, 7, 6, 8}, min, lost;

	for (int i = 0; i < size - 1; i++){
		min = i;
		for (int j = i + 1; j< size; j++){

			if (x[min] > x[j]){
				min = j;
			}
			

		}

		cout << x[min] << "  ";
	}

	cin.get();
	cin.get();
	return 0;
}

[Cutefriendzoned]

pls help

[tipaye]

Your assignment in line 18 -- you're assigning one index to another, not swapping the values they point at.
Instead of
min = j
try

int tmp = x[i + 1];
x[i + 1] = x[i];
x[i] = tmp;

Also you don't need so many variables and your "cout" is in the wrong place. You print out 1 value each pass through the loop while sorting, you should rather wait till your sort is complete then print out your final values. See example below:

#include <iostream>

using namespace std;

int main()
{

	int x[] =  {5, 3, 7, 6, 8};
	size_t size = sizeof(x) / sizeof(x[0]);
	while (size > 1)
	{
		for (size_t i = 0; i < size - 1; i++)
		{
			
			if (x[i] > x[i + 1])
			{
					int tmp = x[i + 1];
					x[i + 1] = x[i];
					x[i] = tmp;
			}
		}
		
		--size;	
	}

	for (size_t i = 0; i < (sizeof(x) / sizeof(x[0])); ++i)
	{
		cout << x[i] << endl;
	}
	
	cin.get();
	return 0;
}

[rich1]

you should go through this program step-by-step and than you'll find out what's wrong with that.

i = min = 0
j = 1
x[0] > x[1] -- that's true (5 > 3) and so min = j = 1
... no other comparison will be true; there ain't smaller number than 3
OUTPUT: x[1] = 3

i = min = 1
j = 2
x[1] > x[2] -- false (3 > 7)
... no other comparison will be true; there ain't smaller number than 3 and min is still 1
OUTPUT: x[1] = 3

i = min = 2
j = 3
x[2] > x[3] -- that's true (7 > 6) and so min = j = 3
... no other comparison will be true; there ain't smaller number than 6 and min is still 3
OUTPUT: x[3] = 6

i = min = 3
j = 4
x[3] > x[4] -- false (6 > 8)
... no other comparison will be true; there ain't smaller number than 6 and min is still 3
OUTPUT: x[3] = 6

end

[tipaye]

About the pointers,

If you have void function(int *x)
You can call it by passing a pointer. The pointer is the address of an int, e.g.

int x = 0;
funtcion(&x);

In this case, "&" means "address of"

You may have a function that takes a reference, say
void function(int &y) here "&" means reference to.
You call it by doing

int x = 0;
function(x)

When you're calling this time there's no distinction from how you would pass a normal non-reference, non-pointer argument. However the function you're calling can change the argument. It may help to think of the reference as an automatically generated and de-referenced pointer.

[Cutefriendzoned]

Thanks guys , it worked , I think the program was running fine the only thing is that I tried to do it without the swapping thing , but after doing the swapping , it worked like charm.

#include <iostream>
#include <iomanip>
using namespace std;



int main()
{

	const int size = 5;
	int x[size] {5, 3, 12, 11, 8}, min, lost;

	for (int i = 0; i <= size - 1; i++){
		min = i;
		for (int j = i + 1; j< size; j++){

			if (x[min] > x[j]){
				lost = x[min];
				x[min] = x[j];
				x[j] = lost;
			}
			

		}

		cout << x[min] << "  ";
	}

	cin.get();
	cin.get();
	return 0;
}

could you guys answer my first question please ?