Printing an array with Pointer = Backwards

[XenoCode]

I'm trying to print an array with "Pointer Arithmetic" but it's coming out backwards.

  #include <iostream>
int main(void)
{
	int j[] = {5, 2};
	int* pJ = j; //&j[0]; // Should point to the first element in the array j.

	std::cout << *pJ << "\n" << *pJ++ << std::endl; // This prints 2, 5 instead of the expected 5, 2.

for(int i = 0; i < sizeof(j)/4; i++)
		std::cout << j[i] << std::endl; // This prints the array correctly.


return 0;
}

Also if *pJ is pointing to 2 at position j[1] then wouldn't incrementing the pointer *pJ++ go to j[2] (A non existent location?)

Thanks for your help.

[cire]

*pJ and *pJ++ may be evaluated in any order on line 7, and results in undefined behavior.

Try:

std::cout << *pJ << "\n" << *(pJ+1) << std::endl ;

[XenoCode]

That works but I'm still not clear on how the order of operations changed from your line to mine. Is it due to the parentheses?

[cire]

In yours, you modify the pointer. In mine, the pointer is not modified, so the order in which the expressions are evaluated makes no difference.