C++

Forum

 
trying to output a circle drawn in "X's"

soapasics (2)
trying to create a program to display a circle drawn in "X's".
i'm using an array which stores the "X's" at the elements selected by x- and y-coordinates. the output doesn't look like a circle, though. please help.

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
 
#include <iostream>
#include <math.h>

using namespace std;

int xCoordinate(int rad, int raysAngle, int a)
{
    int xC;
    xC = 4+(rad*cos(raysAngle));
    cout << "angle: " << raysAngle << ". xC " << "#" <<a << ": " << xC << " ";

return xC;
}

int yCoordinate(int rad, int raysAngle, int a)
{
    int yC;
    yC = 4+(rad*sin(raysAngle));
    cout << "yC " << "#" << a << ": " << yC << " " << endl;

return yC;
}

int display(int rad, int grid)
//displays a square grid that is 'grid' units per side.  draws a  circle using X's that has a radius of rad.
//x and y coordinates computed using trigonometric functions in functions xCoordinate and yCoordinate.
{
    int powgrd = pow(grid,2);

    char dArray[powgrd];

    int rays = 4*(rad-1);
    float theta = 360/rays;
    int raysAngle;
    char * xCoords, *yCoords;
    xCoords = new char [rays];
    yCoords = new char [rays];

    for(int a=0;a<rays;a++)
        {
            raysAngle = a*theta;
            xCoords[a] = xCoordinate(rad, raysAngle, a);
            yCoords[a] = yCoordinate(rad, raysAngle, a);
        }


int n = 0;
for(int a = 0; a < powgrd; a++)
{
    dArray[a] = '.';
}

while(n < powgrd)
{
    cout << n << ": " << ((grid*yCoords[n])+xCoords[n]) << " ";
    n++;

}

cout << "\n\n\n";
int b = 0, c = 0;
    while (b < powgrd)
    {
        while (c < powgrd)
        {
            if (b == ((grid*yCoords[c])+xCoords[c]))
            {
                dArray [b] = 'X';
                c++;
            }
            else
            {
                c++;
            }
        }
        b++;
        c=0;
}


cout << "\n\n\n";

// displays the array in a grid shape
for (int a = 1;a <= powgrd; a++)
    {
        cout << dArray[a-1] << " ";
        if (a % grid == 0)
        {
        cout << endl;
        }
    }

    return 0;
}

int main()
{
    int rad = 8;
    int grid = 20;


    display(rad, grid);
    return 0;
}
[code]
[/code]
Last edited on
CplusplusAcolyte (170)
Your code would be more readable in code tags. As far as the circle you wish to create, do you already have an idea of where the X's are supposed to be? One simple answer is to have the array filled with ones where X's are supposed to go, and zeros everywhere else. When outputting the array, when any value besides zero is found, an X can be outputted instead of a space. Of course, you'd have to initialize your array based on the value of rad, though.
soapasics (2)
sorry - here it is in code tags.

thanks, ill try it.
Topic archived. No new replies allowed.