Using the bubble sort

[jjaworski321]

For some reason calling my bubble sort function to main is not working. It reads out:
Error: argument of type "char(*)[30]" is incompatible with parameter of type "char*"

What am I doing wrong?

#include <iostream>
#include <cstring>

using namespace std;



void outputwords (const char strings [][30]);
void getnumbers (char strings[][30]);
void sortArray (char strings[],int size);
void showArray (const char strings[],int size);

int main ()
{
	char strings[25][30];
	getnumbers(strings);
	outputwords(strings);
	sortArray (strings, 25);
	showArray (strings, 25);
	
	system ("pause");
	return 0;
}

void getnumbers (char strings[][30])
{
		cout<<"Please enter a list of animal names, ending the list with a period."<<endl;

	for (int i = 0;i < 25; i++)
	{
		cin >> strings[i];
		if (strcmp(strings[i],".")==0)
		{
			break;
		}
	}
}

void outputwords (const char strings [][30])
{
		
	for (int i = 0; i < 25;i++)
	{
		cout<< strings[i]<<" ";

		if (strcmp(strings[i],".")==0)
		{
			break;
		}
	}
}

void sortArray (char strings [25], int size)
{
	bool swap;
	char temp;

	do
	{
		swap = false;
		for (int count = 0; count < (size-1); count++)
		{
			if (strings[count] > strings[count+1])
			{
				temp = strings[count];
				strings[count] = strings[count+1];
				strings[count+1] = temp;
				swap = true;
			}
		}
	} while (swap);
}

void showArray (const char strings[], int size)
{
	for (int count = 0; count < size; count++)
		cout << strings[count] << " ";
		cout << endl;
}

[ats15]

sortArray (and showArray) take an 1D array of chars as an argument, and in main you pass a 2D array