output strange?

[4LzRX9L8]

Simple program that asks for my name then returns name, but instead of full name i only get the first character of the name.

  #include <iostream>

using namespace std;

int main()
{
    char myName ;
    cout << "Hello, what is your name?\n";
    cin >> myName ;
    cout << "Hello " << myName << "\n";
}

Where am I doing a mistake?

Edit: Just realised changing myName from char to string and including <string> solved my problem. Is char only supposed to be one character?

[The illusionist mirage]

Your mistake:

char myName ;

It should be

char myName[CHAR_ARRAY_SIZE_GOES_HERE] ;

[4LzRX9L8]

So the default array size for char is one?

[MikeyBoy]

No. char is not an array. char is a single character.

There is no default size for an array. When you create an array, you have to specify the size.

[The illusionist mirage]

char myName ;

This just declares a character variable. If you want to declare an array, you'll have to use square braces immediately after the identifier and specify the number of elements in it. There is no defualt size in an array.

http://www.cplusplus.com/doc/tutorial/arrays/

[4LzRX9L8]

Yes, that's what I said. The default array size for char is then a single character. If however I change the array size with [] to [10] the size of the elements become 10 instead of a single character. Right?

Edit: [10] would make the elemenets 11 not 10.

[MikeyBoy]

The default array size for char is then a single character.

NO! char is not an array. If you write:

char myName ;

then there's no default array size of 1, because there is no array of any kind there!

[The illusionist mirage]

char myName[]; will give an error. And I tell you again there's no default array size. char myName ; is a variable declaration, not an array declaration.

[4LzRX9L8]

Sorry after looking up what an array is I now understand.

Thank you very much!