Pointers and type casting

[amitk3553]

I had put 99 on hci_ll_pkt_val[0], but I am not getting this value of 99 on hci_ll_pkt_arr[0] ??

unsigned char* hci_ll_pkt_arr;                                 
int* hci_ll_pkt_val;      

cout<<"@"<<sc_time_stamp()<<"\t\t hci_ll_pkt_val = "<<hci_ll_pkt_val[i]   <<"\n";                              
          
hci_ll_pkt_arr = reinterpret_cast<unsigned char*>(hci_ll_pkt_val); 
 
cout<<"@"<<sc_time_stamp()<<"\t\t hci_ll_pkt_arr = "<<hci_ll_pkt_arr[0]<<"\n";                              
  
  

Regards
cam

[MikeyBoy]

hci_ll_pkt_arr is an array of chars, not ints. So when cout prints out that array element, it will display it as a char. It will display the character with an ASCII code value of 99.

[coder777]

a pointer cast does not change anything pointed to.

in other words: you have an unsigned char pointer that points to a sequence of ints. You need to know how the ints are organized in memory in order to tell what the output is when used as unsigned char