Help please

[mkory]

I need some help with this program.
The task is to write a complete program that evaluate a formula in terms of y and x. The formula is y=x*x*x*x-x*x*x-7*x*x+x+6/(abs(x-))+sqrt(5-x)
the program should evaluate the formula starting with x=-4. going up by 0.5 until reaches 3 . If value of y is 0, the message after output should be Y IS 0, if the value of y is positive, the message should say is positive, if the value of y is negative, the message should say y is negative/

In addiction to the above:
Have your program find which of the y values is closest to 1. Have the program print the x value that gives this closest y value. Also print how close y value is to 1/ Have your program count how many times the formula is positive, negative and how many times it is zero.
I have trouble with in addition part.
here is the code i have so far.

#include <iostream>
#include <cmath>
using namespace std;
int main()
{
double x,y;
cout<<"\t\tTable of Function Values"<<endl<<endl;
for (x=-3;x<=4;x=x+0.5)
{
y=(x*x*x*x-x*x*x-7*x*x+x+6)/(abs(x-3)+sqrt(5-x));
cout<<'\t'<<x<<"\t\t"<<y;
if (y==0)
cout<< "\t\t Y is Zero"<<endl;
if (y<0)
cout<<"\t Y is negative"<<endl;
if (y>0)
cout<<"\t\t Y is positive"<<endl;
cout <<endl;

}
cout <<endl<< "The table is finished"<<endl;
return 0;
}

Please help me find which of the y values is closest to 1. Have the program print the x value that gives this closest y value. Also print how close y value is to 1/ Have your program count how many times the formula is positive, negative and how many times it is zero.
I have trouble with in addition part.
here is the code i have so far. Your help will be appreciated thank you.