I need for loop help

[bknick24]

I am finishing up some homework on for loops. I am stuck on a couple of the questions. I need to make this for loop output a number given for x - 0.5. x is given as an input by the user. Here is what I have for this:

double x;
     cout << "Enter a value for 'x': " << endl;
     cin >> x;
     
     for (double x; x<=0.5; x++)
     cout << x - 0.5 << endl;

Right now it does not output anything after the user inputs x.

My next question is how would I go about making a for loop that prompts the user for 10 integers and then it outputs the number of even and odd numbers? I think I could do this with a while loop easier but the assignment requires me to do it with a for loop.

Any help is much appreciated.

[crimsonzero2]

Instead of using double x within the for loop, use a different name, ex: double a.

When you have it recall x, it will just erase the input from earlier in the code. This most likely causes nothing to be outputted cause x is most likely a random big number greater than 0.5.

The other thing x++ would increment by 1 and I'm not sure if you are purposely doing this or not. I most likely think you want to increment by 0.1. ex: x += 0.1.

So overall, your for loop should look like: for(double a = x; a <= 0.5; a += 0.5).

Or even yet, you could try this: for(x; x <= 0.5; x += 0.5).

I hope any of this helps.

[bknick24]

Even if I have my code set up like this:

 double x;
     cout << "Enter a value for 'x': " << endl;
     cin >> x;
     
     for(double n; n<=0.5; x+=0.5)
     cout << x - 0.5 << endl;
     }

It does still not output anything

[crimsonzero2]

You got to have n = x at the beginning:
double n = x;

And at the end you would want to increment n:
n+= 0.5;

And within the for loop you would want n for output:
cout << n - 0.5 << endl;

[Bourgond Aries]

The reason you need double n = something; is because it is unspecified what a POD stack variable will hold when not initialized. It could contain 0, or "garbage" data that was previous in memory.

     double x;
     std::cout << "Enter a value for 'x': " << std::endl;
     std::cin >> x;
     
     for(double n(0.); n<=0.5; x+=0.5)
     { // You forgot the { I suppose; or is the ending } part of another control structure?
         std::cout << (x - 0.5) << std::endl;
     }

[bknick24]

double x;
     cout << "Enter a value for 'x': " << endl;
     cin >> x;
     
     for(double n = x; n>=0.5; x+=0.5)
     cout << x - 0.5 << endl;
     }

I have this now and it still does not output anything.. any ideas?

[bknick24]

any ideas??

[topnik1]

I am not really sure what u want but is this your point?

double x;
     cout << "Enter a value for 'x': " << endl;
     cin >> x;
     
     for (x; x>=0.5; x=x-0.5)
     cout << x - 0.5 << endl;

[topnik1]

For your second problem is this what you want?

#include<iostream>
using namespace std;
int main()
{
	int a[10],odd=0,even=0;
	for(int i=0;i<10;i++)
		cin>>a[i];
	/*after you input your numbers*/
	for(int i=0;i<10;i++)
	{
		if(a[i]%2==1)odd++;
		else
			even++;
	}
    cout<<odd<<endl<<even<<endl;
	system("PAUSE");
	return 0;
}

or you can check everyone individually for every cin check the %2== ....