function

[krisapp]

Write a program that accepts a positive integer value n and uses a function to calculate 12

+ 22
+ 32
+ ... + n
2
for the given value n. The result should be returned to the main
function and displayed.
---------------------------------------------------------------------------------
#include<iostream>
using namespace std;
int sum(int n);

int main()
{
int n,sumz;
cout<<"enter your number:";
cin>>n;
sumz=sum(n);
cout<<n<<" "<<sumz<<endl;
return 0;

}

int sum(int n)
{
int f=1;
for(int i=n;i>=1;i++)
f=(f*i)+(f*i);
return f;
}

can u help me to solve the problme...

[Tang87]

In your for loop you have it looping forever (i > 1 then increment. If you decrement it'll satisfy the condition) I'm not completely sure what math the function is supposed to be done maybe I'm reading it wrong.

[krisapp]

in fact it is suposed to print the total of the square number i.e if 1 enter 2..it must calculate the total of 1 to the square = 2 to the square.... but anyway i have solve the problem already...


int sum(int n)
{
int sum=0,f=1;
for(int i=1;i<=n;i++)
{
f=(i*i);
sum=sum+f;
}
return sum;
}