problem with classes in C++

created class of 'natural numbers' for arithmetic operations I started writing code
I started to solve correctly???
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#include<iostream.h>
#include<conio.h>
#include<fstream.h>
#include<math.h>
#include<string.h>
class natural{
public :
char x[10000];

friend natural operator+(natural,natural);
friend natural operator+(natural,unsigned int);
friend natural operator-(natural,natural);
friend natural operator-(natural,unsigned int);
friend natural operator*(natural,natural);
friend natural operator/(natural,natural);
friend int operator==(natural,natural);
natural operator=(natural);
friend ostream& operator << (ostream& os,natural z);
friend istream& operator >> (istream& is,natural z);    };

natural operator+(natural a,natural b){
natural c;
int o[1000],m[1000],n[1000],l,l1,lt,d,r,i;
for(i=0;i<strlen(a.x);i++)
m[i]=a.x[i]-48;
for(i=0;i<strlen(b.x);i++)
n[i]=b.x[i]-48;  l=strlen(a.x); l1=strlen(b.x);
if(l>l1) {lt=l; d=l-l1;
for(i=l1-1;i>=0;i--)
n[i+d]=n[i];
for(i=0;i<d;i++)
n[i]=0; }
else  {lt=l1; d=l1-l;
for(i=l-1;i>=0;i--)
m[i+d]=m[i];
for(i=0;i<d;i++)
m[i]=0; }
r=0;
for(i=lt-1;i>-1;i--)
{o[i]=(m[i]+n[i]+r)%10; r=(m[i]+n[i])/10;
}
for(i=0;i<lt;i++)
c.x[i]=o[i]+48;
return c;}

natural operator+(natural a,unsigned int b){
natural c;
int o[1000],m[1000],n[1000],l1,l2,lt,d,r,i;
for(i=0;i<strlen(a.x);i++)
m[i]=a.x[i]-48;
lt=l2=strlen(a.x);
l2--;
while(b!=0)
{n[l2]=b%10;
b=b/10;l2--; }
for(i=0;i<=l2;i++)
n[i]=0;
for(i=0;i<lt;i++)
 cout<<n[i];
   cout<<endl;
r=0;
for(i=lt-1;i>-1;i--)
{o[i]=(m[i]+n[i]+r)%10; r=(m[i]+n[i])/10;
}
for(i=0;i<lt;i++)
c.x[i]=o[i]+48;
return c;}

natural operator-(natural a,natural b){
natural c;
int o[1000],m[1000],n[1000],l,l1,lt,d,r,i;
for(i=0;i<strlen(a.x);i++)
m[i]=a.x[i]-48;
for(i=0;i<strlen(b.x);i++)
n[i]=b.x[i]-48;  l=strlen(a.x); l1=strlen(b.x);
if(l>l1) {lt=l; d=l-l1;
for(i=l1-1;i>=0;i--)
n[i+d]=n[i];
for(i=0;i<d;i++)
n[i]=0; }
else  {lt=l1; d=l1-l;
for(i=l-1;i>=0;i--)
m[i+d]=m[i];
for(i=0;i<d;i++)
m[i]=0; }
r=0;
for(i=lt-1;i>-1;i--)
{if((m[i]>n[i]) ||(m[i]==n[i])) o[i]=m[i]-n[i];
 else {o[i]=m[i]+10-n[i]; r=i; m[r-1]--; }
 }
for(i=0;i<lt;i++)
c.x[i]=o[i]+48;
return c;}

natural operator-(natural a,int b){
natural c;
int o[1000],m[1000],n[1000],l,l1,lt,d,r,i;
for(i=0;i<strlen(a.x);i++)
m[i]=a.x[i]-48;
lt=l1=strlen(a.x);
l1--;
while(b!=0)
{n[l1]=b%10;
b=b/10;l1--; }
for(i=0;i<=l1;i++)
n[i]=0;
for(i=0;i<lt;i++)
cout<<n[i];cout<<endl;

r=0;
for(i=lt-1;i>-1;i--)
{if((m[i]>n[i]) ||(m[i]==n[i])) o[i]=m[i]-n[i];
 else {o[i]=m[i]+10-n[i]; r=i; m[r-1]--; }
 }
for(i=0;i<lt;i++)
c.x[i]=o[i]+48;
return c;}


int operator==(natural a,natural b)  { int ok;ok=1;
if(strlen(a.x)!=strlen(b.x)) ok=0;
else {for(int i=0;i<strlen(a.x);i++)
     if(a.x[i]!=b.x[i])
	   ok=0;  }
if (ok!=1) return 0;
else return 1;
}

ostream& operator << (ostream& os,natural z){
for(int i=0;i<strlen(z.x);i++)
os<<z.x[i];
return os;}

istream& operator >> (istream& is,natural& z){
is>>z.x;
return is;}

main ()
{clrscr();
natural w,y;
unsigned int t;
 char f;

do{
 cout<<"1-natural+natural"<<endl;
 cout<<"2-natural+int"<<endl;
 cout<<"3-natural-natural"<<endl;
 cout<<"4-natural-int"<<endl;
 cout<<"5-natural*natural"<<endl;
 cout<<"6-natural/natural"<<endl;
 cout<<"0-exit"<<endl;
 cin>>f;
  switch(f)
  {
   case '1': cout<<"---------natural+natural--------"<<endl;
 cout<<"introdu valoarea numarului natural"<<"\n";
 cin>>w.x;
  cin>>y.x;
   cout<<"valorile introduse:"<<"\n";
cout<<"w="<<w<<"\n";
cout<<"y="<<y<<"\n";
 cout<<w+y<<endl;
 if(w==y)
cout<<"numerele sint egale";
else cout<<"numerele sint diferite"; cout<<endl;
break;
case '2': cout<<"--------natural + int------"<<endl;
 cout<<"dati un nr natural:";
 cin>>w.x;
  cout<<"dati un nr int:";
 cin>>t;
 cout<<w+t<<endl;  break;
 case '3':cout<<"-----------natural-natural------------"<<endl;
 cout<<w-y<<endl; break;
  default : cout<<"operatie necunoscuta:";cout<<endl;}}
   while(f!='0');

}
Well, your coding technique is unreadable. The space bar and the ENTER keys are your friends...

Also, somehow, without even trying to understand what you are doing, I think that the operators can be implemented in less than 9 local variables. Consider simplifying the code.

Having said that, operator== should return bool, not int;
operator= should return natural& (ie, *this);

Consider using boost::operators for a lot of this; you'll get a bunch of the functions for free.

and - 48 would be better written as - '0'
Last edited on
holy santa clause shit, Im lost

how to write constructor and destructor for this class??????????????
Just one question mark is enough

to write a constructor you need to put in the class a function with no return type specified and the same name of the class,
for the destructor the same thing but adding a ~ before the class name:
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class C
{
    public:
        C(/*parameters*/) : initializer(list) { /*constructor body*/ }
        ~C() { /*destructor body*/  }
}

http://www.cplusplus.com/doc/tutorial/classes/
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